Sliding window

Find a Clean Signal

Original & variantLongest Substring Without Repeating Characters ↗

This version returns the actual substring, with earliest ties, instead of its length.

01. The question

A receiver records lowercase letter codes. Return the longest continuous segment with no repeated code, not just its length. If segments tie, return the earliest one.

Before revealing the idea, predict the result and describe what information you would need to track.

02. Worked example

Inputsignal = "cabinabc"

Output"cabin"

  1. The first five letters form "cabin", with no repeated code.
  2. The next a repeats the earlier a. Move the left edge past its previous position.
  3. The final window "inabc" also has five letters. Keep "cabin", because it appeared first.

Try your code

Define solve(data, parameter="") and return your result. Your code runs locally, not on a server.

Edit your test cases

Use 1-10 objects with data and an optional string parameter. Expected outputs are computed from the lesson. An optional expected field must be correct.

Input contract & reference code

Example data: "cabinabc". Parameter: "". Numeric parameters arrive as strings; convert them with int(parameter) when needed.

The example and generated cases use the question’s exact variant. This checks behavior on a small test batch—not performance on every possible input.

Python runtime notices

Python downloads only when you run code, using compressed runtime assets. Code is not saved or uploaded. Enable JavaScript to run it.

Five-second execution limit per batch. Standard-library Python only; additional packages and network access are unavailable. Stop ends execution without blocking the lesson.

03. The idea

Try sketching your own approach first. What would you track, and why would it work?

Reveal the idea
  1. Remember where each letter last appeared.
  2. Move the left edge forward when a repeat would break the window.
  3. Save a new best start only when the valid window is strictly longer. Return the saved slice.

04. Watch it happen

Use Step to move slowly, or Play to follow the whole trace. Change a preset or load your own input.

Input & settings

Up to 40 lowercase a-z codes. Empty input is allowed. Ties keep the earliest segment.

Red = current item / blue = active window or cells / green = completed work. A value docks at its actual destination; the original input stays unchanged. Positions start at 0.

Working state / what changes

Ready to begin

Enable JavaScript to step through the animation. The worked example and solution below remain readable without it.

Python / why it changes

The line behind the step

def clean_signal(signal: str) -> str:
    last_seen = {}
    left = best_start = best_length = 0
    for right, character in enumerate(signal):
        if character in last_seen:
            left = max(left, last_seen[character] + 1)
        last_seen[character] = right
        length = right - left + 1
        if length > best_length:
            best_start, best_length = left, length
    return signal[best_start:best_start + best_length]
How to use this walkthrough

Hover or focus a control for its label. Play forms the input and follows values into the working state. Step shows one change; Back and the slider restore exact snapshots. Reduced motion uses instant updates. Saved snapshots and sorted heap displays are teaching overhead, not algorithm complexity.

05. Python solution

def clean_signal(signal: str) -> str:
    last_seen = {}
    left = best_start = best_length = 0
    for right, character in enumerate(signal):
        if character in last_seen:
            left = max(left, last_seen[character] + 1)
        last_seen[character] = right
        length = right - left + 1
        if length > best_length:
            best_start, best_length = left, length
    return signal[best_start:best_start + best_length]

06. Cost & edge cases

Time
O(n) expected
Space
O(min(n, alphabet size))
  • An empty signal returns "". Input codes are lowercase a-z.
  • "zzzz" returns "z".
  • "noon" returns "no": never move left backward and keep the earliest tied answer.

Keep going