Length-prefixed framing

Pack Labels Without Escaping

Original & variantEncode and Decode Strings ↗

Original examples and wording. The question below states the exact input format and output contract.

01. The question

Given a JSON list of ASCII strings (including empty strings and # marks), return {"encoded": string, "decoded": list}. Frame each label as decimal character length, #, then exactly that many characters. Decode your own encoding and preserve every label.

Before revealing the idea, predict the result and describe what information you would need to track.

02. Worked example

Input["box#7","","hi"]

Output{"encoded":"5#box#70#2#hi","decoded":["box#7","","hi"]}

  1. "box#7" has five characters, so its frame is "5#box#7".
  2. The empty label is "0#"; "hi" is "2#hi".
  3. Read a length up to #, then consume that exact payload length; payload # marks are ordinary data.

Try your code

Define solve(data, parameter="") and return your result. Your code runs locally, not on a server.

Edit your test cases

Use 1-10 objects with data and an optional string parameter. Expected outputs are computed from the lesson. An optional expected field must be correct.

Input contract & reference code

Example data: ["box#7","","hi"]. Parameter: "". Numeric parameters arrive as strings; convert them with int(parameter) when needed.

The example and generated cases use the question’s exact variant. This checks behavior on a small test batch—not performance on every possible input.

Python runtime notices

Python downloads only when you run code, using compressed runtime assets. Code is not saved or uploaded. Enable JavaScript to run it.

Five-second execution limit per batch. Standard-library Python only; additional packages and network access are unavailable. Stop ends execution without blocking the lesson.

03. The idea

Try sketching your own approach first. What would you track, and why would it work?

Reveal the idea
  1. Join independently length-prefixed frames.
  2. Read each decimal header up to its separator.
  3. Slice the announced payload and move the cursor past it.

04. Watch it happen

Use Step to move slowly, or Play to follow the whole trace. Change a preset or load your own input.

Input & settings

Bounded original examples: at most 16 list nodes, 12 intervals, 16 labels or 40 ASCII characters. Pointer identities and interval endpoint rules are stated in the task.

Red = current item / blue = active window or cells / green = completed work. A value docks at its actual destination; the original input stays unchanged. Positions start at 0.

Working state / what changes

Ready to begin

Enable JavaScript to step through the animation. The worked example and solution below remain readable without it.

Python / why it changes

The line behind the step

def solve(data, parameter=''):
    pieces = []
    for word in data:
        pieces.append(str(len(word)) + "#" + word)
    encoded = "".join(pieces)
    decoded = []
    cursor = 0
    while cursor < len(encoded):
        separator = encoded.index("#", cursor)
        length = int(encoded[cursor:separator])
        start = separator + 1
        decoded.append(encoded[start:start + length])
        cursor = start + length
    return {"encoded": encoded, "decoded": decoded}
How to use this walkthrough

Hover or focus a control for its label. Play forms the input and follows values into the working state. Step shows one change; Back and the slider restore exact snapshots. Reduced motion uses instant updates. Saved snapshots and sorted heap displays are teaching overhead, not algorithm complexity.

05. Python solution

def solve(data, parameter=''):
    pieces = []
    for word in data:
        pieces.append(str(len(word)) + "#" + word)
    encoded = "".join(pieces)
    decoded = []
    cursor = 0
    while cursor < len(encoded):
        separator = encoded.index("#", cursor)
        length = int(encoded[cursor:separator])
        start = separator + 1
        decoded.append(encoded[start:start + length])
        cursor = start + length
    return {"encoded": encoded, "decoded": decoded}

06. Cost & edge cases

Time
O(C + n), where C is the total payload length
Space
O(C + n), including encoded and decoded outputs
  • [] encodes as "" but [""] encodes as "0#".
  • Digits, separators, quotes and ASCII control characters survive JSON decoding.
  • This is character framing for ASCII, not a UTF-8 byte protocol or an external packet validator.

Keep going