Kadane's algorithm
Choose the Strongest Energy Run
01. The question
Signed readings represent energy gained or lost at consecutive stations. Return the largest sum of a nonempty continuous run. At least one reading is required.
Before revealing the idea, predict the result and describe what information you would need to track.
02. Worked example
Inputreadings = [-3, 4, -1, 2, -6, 3]
Output5
- Start a new run at 4 rather than carrying the earlier -3.
- Extending through -1 and 2 raises its sum to 5.
- The later -6 does not erase the best completed run.
Try your code
Define solve(data, parameter="") and return your result. Your code runs locally, not on a server.
Edit your test cases
Use 1-10 objects with data and an optional string parameter. Expected outputs are computed from the lesson. An optional expected field must be correct.
Input contract & reference code
Example data: [-3,4,-1,2,-6,3]. Parameter: "". Numeric parameters arrive as strings; convert them with int(parameter) when needed.
The example and generated cases use the question’s exact variant. This checks behavior on a small test batch—not performance on every possible input.
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Printed output
Five-second execution limit per batch. Standard-library Python only; additional packages and network access are unavailable. Stop ends execution without blocking the lesson.
03. The idea
Try sketching your own approach first. What would you track, and why would it work?
Reveal the idea
- At each station, either extend the previous run or restart here.
- Keep the best sum ending here separate from the best sum anywhere.
- Initialize with the first reading, not 0.
04. Watch it happen
Use Step to move slowly, or Play to follow the whole trace. Change a preset or load your own input.
Input & settings
Red = current item / blue = active window or cells / green = completed work. A value docks at its actual destination; the original input stays unchanged. Positions start at 0.
Working state / what changes
Ready to begin
Enable JavaScript to step through the animation. The worked example and solution below remain readable without it.
Python / why it changes
The line behind the step
def energy_run(readings):
ending = best = readings[0]
for value in readings[1:]:
ending = max(value, ending + value)
best = max(best, ending)
return bestHow to use this walkthrough
Hover or focus a control for its label. Play forms the input and follows values into the working state. Step shows one change; Back and the slider restore exact snapshots. Reduced motion uses instant updates. Saved snapshots and sorted heap displays are teaching overhead, not algorithm complexity.
05. Python solution
def energy_run(readings):
ending = best = readings[0]
for value in readings[1:]:
ending = max(value, ending + value)
best = max(best, ending)
return best06. Cost & edge cases
- Time
- O(n)
- Space
- O(1)
- All-negative readings return the least-negative reading.
- The empty run is not permitted.