Three-pointer reversal

Turn a Relay Chain Around

Original & variantReverse Linked List ↗

Original examples and wording. The question below states the exact input format and output contract.

01. The question

Build a singly linked relay chain from a JSON list of integer readings. Reverse its next pointers and return the readings reached from the new head. Node identity is its original index, even for equal readings.

Before revealing the idea, predict the result and describe what information you would need to track.

02. Worked example

Input[4,4,9,2]

Output[2,9,4,4]

  1. Save node 0’s old successor before pointing node 0 to null.
  2. Point node 1 toward node 0, then continue using the saved successor.
  3. The former final node becomes the new head.

Try your code

Define solve(data, parameter="") and return your result. Your code runs locally, not on a server.

Edit your test cases

Use 1-10 objects with data and an optional string parameter. Expected outputs are computed from the lesson. An optional expected field must be correct.

Input contract & reference code

Example data: [4,4,9,2]. Parameter: "". Numeric parameters arrive as strings; convert them with int(parameter) when needed.

The example and generated cases use the question’s exact variant. This checks behavior on a small test batch—not performance on every possible input.

Python runtime notices

Python downloads only when you run code, using compressed runtime assets. Code is not saved or uploaded. Enable JavaScript to run it.

Five-second execution limit per batch. Standard-library Python only; additional packages and network access are unavailable. Stop ends execution without blocking the lesson.

03. The idea

Try sketching your own approach first. What would you track, and why would it work?

Reveal the idea
  1. Construct actual nodes at the input boundary.
  2. Save following before changing current.next.
  3. Move previous and current forward until the unprocessed chain is empty.

04. Watch it happen

Use Step to move slowly, or Play to follow the whole trace. Change a preset or load your own input.

Input & settings

Bounded original examples: at most 16 list nodes, 12 intervals, 16 labels or 40 ASCII characters. Pointer identities and interval endpoint rules are stated in the task.

Red = current item / blue = active window or cells / green = completed work. A value docks at its actual destination; the original input stays unchanged. Positions start at 0.

Working state / what changes

Ready to begin

Enable JavaScript to step through the animation. The worked example and solution below remain readable without it.

Python / why it changes

The line behind the step

class Node:
    def __init__(self, value):
        self.value = value
        self.next = None

def chain(values):
    dummy = Node(None)
    tail = dummy
    for value in values:
        tail.next = Node(value)
        tail = tail.next
    return dummy.next

def values(head):
    result = []
    while head is not None:
        result.append(head.value)
        head = head.next
    return result

def solve(data, parameter=''):
    current = chain(data)
    previous = None
    while current is not None:
        following = current.next
        current.next = previous
        previous = current
        current = following
    return values(previous)
How to use this walkthrough

Hover or focus a control for its label. Play forms the input and follows values into the working state. Step shows one change; Back and the slider restore exact snapshots. Reduced motion uses instant updates. Saved snapshots and sorted heap displays are teaching overhead, not algorithm complexity.

05. Python solution

class Node:
    def __init__(self, value):
        self.value = value
        self.next = None

def chain(values):
    dummy = Node(None)
    tail = dummy
    for value in values:
        tail.next = Node(value)
        tail = tail.next
    return dummy.next

def values(head):
    result = []
    while head is not None:
        result.append(head.value)
        head = head.next
    return result

def solve(data, parameter=''):
    current = chain(data)
    previous = None
    while current is not None:
        following = current.next
        current.next = previous
        previous = current
        current = following
    return values(previous)

06. Cost & edge cases

Time
O(n)
Space
O(1) algorithm workspace; O(n) input-node construction and returned JSON
  • An empty chain returns [].
  • One node points to null before and after reversal.
  • Equal values remain different nodes; reversing an array is not this pointer algorithm.

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